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theorems:goldstones_theorem [2017/09/29 07:28]
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theorems:goldstones_theorem [2020/04/12 15:05] (current)
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 ====== Goldstone'​s theorem ====== ====== Goldstone'​s theorem ======
  
-<tabbox Why is it interesting?> ​ 
- 
-<​blockquote>​ 
-Goldstone'​s theorem states that whenever a continuous global symmetry is spontaneously broken, there exists a massless excitation about the spontaneously broken vacuum. Decomposing $\Phi(x)=|\Phi(x) |e^{i\rho(x)}$,​ $\rho$ transforms as $\rho(x) \to \rho(x) + \theta$. Hence the Lagrangian can depend on $\rho $ only via the derivative = $\partial_\mu \rho$; there cannot be any mass term for $\rho$, and it is a massless field. $\rho$ --- identified as the field which transforms inhomogeneously under the broken symmetry --- is referred to as the Goldstone boson. 
- 
-<​cite>​https://​arxiv.org/​pdf/​1703.05448.pdf</​cite>​ 
-</​blockquote>​ 
- 
-<tabbox Layman> ​ 
  
-<note tip+<tabbox Intuitive>  
-Explanations in this section should contain no formulasbut instead colloquial things like you would hear them during a coffee break or at a cocktail party. +  * For an intuitive explanation of Goldstone'​s theoremsee [[http://​jakobschwichtenberg.com/understanding-goldstones-theorem-intuitively/​|Understanding Goldstone’s theorem intuitively]] by J. Schwichtenberg
-</note>+
   ​   ​
-<​tabbox ​Student+<​tabbox ​Concrete
  
 <​blockquote>​ <​blockquote>​
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 ness and spin waves (figure 9a). In nematic liquid crystals, ness and spin waves (figure 9a). In nematic liquid crystals,
 the broken rotational symmetry introduces an orientational the broken rotational symmetry introduces an orientational
-elastic stiffness (it pours, but resists bending!) +elastic stiffness (it pours, but resists bending!) and rotational waves (figure 9b).
- +
-and rotational waves (figure 9b).+
 In superfluids,​ the broken gauge symmetry leads to a In superfluids,​ the broken gauge symmetry leads to a
 stiffness which results in the superfluidity. Superfluidity stiffness which results in the superfluidity. Superfluidity
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 much simpler and more elegant explanation than we had.** much simpler and more elegant explanation than we had.**
  
 +(11In condensed-matter language, the
 +Goldstone mode produces a chargedensity
 +wave, whose electric fields are
 +independent of wavelength. This gives
 +it a finite frequency (the plasma frequency)
 +even at long wavelength. In
 +high-energy language the photon eats
 +the Goldstone boson, and gains a mass.
 +The Meissner effect is related to the gap
 +in the order parameter fluctuations (~
 +times the plasma frequency), which the
 +high-energy physicists call the mass of
 +the Higgs boson.)
  
-<​cite>​https://​arxiv.org/​pdf/​cond-mat/​9204009.pdf</​cite>​+<​cite>​https://​arxiv.org/​pdf/​cond-mat/​9204009.pdf and http://​pages.physics.cornell.edu/​~sethna/​StatMech/​EntropyOrderParametersComplexity.pdf</​cite>​
 </​blockquote>​ </​blockquote>​
  
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 </​blockquote>​ </​blockquote>​
  
-  
-<tabbox Researcher> ​ 
  
-<note tip> +----
-The motto in this section is: //the higher the level of abstraction,​ the better//. +
-</​note>​+
  
---> Common Question 1#+**Examples**
  
-  +--> Landau phonons in Bose-Einstein condensates#​
-<--+
  
---> Common Question 2#+"The Bose-Einstein condensation is characterized by the 
 +breaking of a global U(1) gauge group (acting on the Bose particle field 
 +as the U(1) group of Example 1), as very clearly displayed by the free 
 +Bose gas.5 The U(1) breaking leads to the existence of Goldstone 
 +modes, the so-called Landau phonons, and the existence of such excitations 
 +may in turn indicate the presence of a broken U(1) symmetry"​ [[https://​arxiv.org/​pdf/​1502.06540.pdf |Source]] ​
  
-  
 <-- <--
-  ​ 
-<tabbox Examples> ​ 
  
---> Example1#+---- 
 + 
 +  * For a nice summary see http://​pages.physics.cornell.edu/​~ajd268/​Notes/​GoldstoneBosons.pdf
  
    
-<--+<tabbox Abstract>​  
 + 
 +<​blockquote>​ 
 +It was known from perturbative investigations of self-interacting scalar fields 
 +by Goldstone that the local current conservation may lead to a divergent global 
 +charge resulting from the contribution of a massless scalar (”Goldstone”) boson 
 +which impedes the large distance convergence and in this way causes a situation 
 +which was appropriately referred to as spontaneous symmetry breaking (SSB). 
 +Kastler, Swieca and Robinson showed that this cannot happen in the presence of a mass gap [12], and in a follow up paper (based on the use of the Jost-Lehmann-Dyson 
 +representation) Swieca together with Ezawa [13] succeeded to 
 +prove the Goldstone theorem in a model- and perturbation- independent way. 
 + 
 +The Goldstone theorem states that a Noether symmetry in QFT is spontaneously broken 
 +precisely if a massless scalar ”Goldstone boson” prevents the convergence of some of the global 
 +charge $Q= \int j_0 = \infty.$ 
 + 
 +This quasiclassical prescription leads to a model-defining first order interaction 
 +density which maintains the conservation of the symmetry currents in 
 +all orders. There are symmetry-representing unitary operators for each finite 
 +spacetime region O but the global charges $Q= \int j_0$ of same symmetry generating 
 +currents diverge. This is the definition of SSB whereas the shift in field 
 +space procedure is a way to prepare such a situation whenever SSB is possible. 
 +For the later presentation of the Higgs model it is important to be aware of a 
 +fine point about SSB whose nonobservance led to a still lingering confusion. As 
 +soon as scalar self-interacting fields are coupled to s = 1 potentials the physical 
 +interpretation of the field shift manipulation on a Mexican hat potential as a 
 +SSB is incorrect; one obtains the Higgs model for the wrong physical reasons 
 +and misses the correct reasons why there can be no self-interacting massive 
 +vectormesons without the presence of a H-field. Although this can be described 
 +correctly in the gauge theoretic formulation,​ a better understanding is obtained 
 +in the positivity preserving string-local setting of LQP (see section 6) 
 + 
 +<​cite>​https://​arxiv.org/​pdf/​1612.00003.pdf</​cite></​blockquote>​ 
 + 
 +<tabbox Why is it interesting?>​  
 + 
 +<​blockquote>​ 
 +Goldstone'​s theorem states that whenever a continuous global symmetry is spontaneously broken, there exists a massless excitation about the spontaneously broken vacuum. Decomposing $\Phi(x)=|\Phi(x) |e^{i\rho(x)}$,​ $\rho$ transforms as $\rho(x) \to \rho(x) + \theta$. Hence the Lagrangian can depend on $\rho $ only via the derivative = $\partial_\mu \rho$; there cannot be any mass term for $\rho$, and it is a massless field. $\rho$ --- identified as the field which transforms inhomogeneously under the broken symmetry --- is referred to as the Goldstone boson. 
 + 
 +<​cite>​https://​arxiv.org/​pdf/​1703.05448.pdf</​cite>​ 
 +</​blockquote>​ 
 + 
 + 
  
---> Example2:# 
  
-  
-<-- 
-  ​ 
-<tabbox History> ​ 
  
 </​tabbox>​ </​tabbox>​
  
  
theorems/goldstones_theorem.1506662912.txt.gz · Last modified: 2017/12/04 08:01 (external edit)