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equations:schroedinger_equation [2018/05/12 12:59]
jakobadmin [Concrete]
equations:schroedinger_equation [2019/05/21 16:55]
michael remove duplicated line in free particle example
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 \begin{align} \begin{align}
-\text{ the classical momentum } p_i \ &​\rightarrow \ i \partial_{x_i} \, .+\text{ the classical momentum } p_i \ &​\rightarrow \ {-i} \hbar \partial_{x_i} \, .
 \end{align} \end{align}
  
-Formulated differently,​ the Hamiltonian operator is calculated from the classical energy $E= T +V$ by replacing the classical momentum $p_i$ with the momentum operator $ \hat{p}_i \equiv i \partial_{x_i}$:​+Formulated differently,​ the Hamiltonian operator is calculated from the classical energy $E= T +V$ by replacing the classical momentum $p_i$ with the momentum operator $ \hat{p}_i \equiv ​{-i} \hbar \partial_{x_i}$:​
  
 \begin{equation} \hat H \equiv - \frac{\hbar^2}{2m} \Delta^2 + \hat V \hat{=} \frac{\hat{p}^2}{2m} + \hat V. \end{equation} \begin{equation} \hat H \equiv - \frac{\hbar^2}{2m} \Delta^2 + \hat V \hat{=} \frac{\hat{p}^2}{2m} + \hat V. \end{equation}
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 It is conventional to denote operators by an additional hat above the classical symbol. ​ It is conventional to denote operators by an additional hat above the classical symbol. ​
  
-The Hamiltonian is what is different for different systems. Formulated differently,​ the Hamiltonian characterizes the system in question. The rest of the Schrödinger equation stays the same for all systems. ​+The Hamiltonian is what is different for different systems. Formulated differently,​ the Hamiltonian characterizes the system in question. The rest of the Schrödinger equation stays the same for all systems. ​For example, the Hamiltonian for a [[models:​basic_models:​harmonic_oscillator|harmonic oscillator]] reads 
 + 
 +\begin{equation} \hat H \equiv ​ \frac{\hat{p}^2}{2m} - \frac{1}{2}k \hat{x}^2 ​  . \end{equation} 
  
 ---- ----
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 \begin{align} \begin{align}
 H  \psi(x)&​= E\psi(x) \notag \\ H  \psi(x)&​= E\psi(x) \notag \\
-\frac{-\hbar \partial_x^2}{2m} \psi(x) &​=E\psi(x) \notag \\ 
 \frac{-\hbar \partial_x^2}{2m} \psi(x) &​=E\psi(x) \notag \frac{-\hbar \partial_x^2}{2m} \psi(x) &​=E\psi(x) \notag
 \end{align} \end{align}
equations/schroedinger_equation.txt · Last modified: 2020/11/21 01:43 by 2a01:cb15:33b:c600:f4a9:8015:b3fa:6b19