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basic_notions:energy [2018/03/28 13:11] jakobadmin |
basic_notions:energy [2018/04/12 16:51] (current) bogumilvidovic [Concrete] |
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<tabbox Concrete> | <tabbox Concrete> | ||
- | <note tip> | + | Energy is the conserved quantity that we derive using Noether's theorem if our system is symmetric under temporal translations. |
- | In this section things should be explained by analogy and with pictures and, if necessary, some formulas. | + | |
- | </note> | + | In addition, energy is responsible for temporal translations. We say energy generates temporal translations. |
- | + | ||
+ | |||
+ | The total energy is defined as | ||
+ | \begin{equation} | ||
+ | E(t) \equiv K(t) + V(q(t)), | ||
+ | \end{equation} | ||
+ | |||
+ | where $K$ denotes the kinetic energy and $V$ the potential energy. | ||
+ | |||
+ | -->Proof the the total energy is conserved# | ||
+ | |||
+ | For a system with a conservative force the relationship between force and potential energy is given by $ | ||
+ | \nabla V \equiv - F$. | ||
+ | |||
+ | In addition, [[equations:newtons_second_law|Newton's second law]] $F = ma$ implies | ||
+ | \[ | ||
+ | \begin{split} | ||
+ | \frac{d}{dt}\left[K(t)+V(q(t))\right] &= F(q(t))\cdot v(t) + | ||
+ | \nabla V(q(t))\cdot v(t) \\ | ||
+ | &= 0, \qquad\text{(because $F=-\nabla V$)}. | ||
+ | \end{split} | ||
+ | \] | ||
+ | |||
+ | <-- | ||
+ | ---- | ||
+ | |||
+ | |||
+ | **Kinetic Energy** | ||
+ | |||
+ | Kinetic energy is defined as | ||
+ | \begin{equation} | ||
+ | K(t) \equiv \frac{1}{2}m\,v(t)\cdot v(t). | ||
+ | \end{equation} | ||
+ | This quantity is useful because | ||
+ | \[ | ||
+ | \begin{split} | ||
+ | \frac{d}{dt}K(t) &= m\,v(t)\cdot a(t) \\ | ||
+ | &= F(q(t))\cdot v(t). | ||
+ | \end{split} | ||
+ | \] | ||
+ | We can see here that the kinetic energy goes up whenever we push an object in the direction | ||
+ | of its velocity. Moreover, it goes down whenever we push it in the opposite | ||
+ | direction. | ||
+ | |||
+ | In addition, we have | ||
+ | \[ | ||
+ | \begin{split} | ||
+ | K(t_1)-K(t_0) &= \int_{t_0}^{t_1} F(q(t))\cdot v(t)\,dt \\ | ||
+ | &= \int_{t_0}^{t_1} F(q(t))\cdot \dot{q}(t)\, dt. | ||
+ | \end{split} | ||
+ | \] | ||
+ | This tells us that the change of kinetic energy is equal to the __work__ done by the | ||
+ | force. The work is defined as the integral of $F$ along the trajectory. | ||
+ | |||
+ | ---- | ||
+ | |||
+ | **Potential Energy** | ||
+ | |||
+ | $ | ||
+ | \nabla V \equiv - F,$ | ||
+ | |||
+ | where $F$ denotes the force. | ||
<tabbox Abstract> | <tabbox Abstract> | ||