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advanced_tools:bianchi_identities [2018/05/03 11:58] jakobadmin [Intuitive] |
advanced_tools:bianchi_identities [2019/01/16 14:35] (current) jakobadmin [Abstract] |
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<tabbox Concrete> | <tabbox Concrete> | ||
+ | For an extremely illuminating discussion see | ||
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+ | * [[https://link.springer.com/article/10.1007%2FBF01882731|The Boundary of a Boundary Principle - a unified approach]] by Arkady Kheyfets. | ||
+ | |||
+ | In addition, good discussion can be found in | ||
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* See chapter 15 in "Gravitation" by Misner Thorne and Wheeler and also | * See chapter 15 in "Gravitation" by Misner Thorne and Wheeler and also | ||
* page 253 in Gauge fields, knots, and gravity by J. Baez | * page 253 in Gauge fields, knots, and gravity by J. Baez | ||
- | + | ---- | |
- | <tabbox Abstract> | + | |
- | <note tip> | + | Bianchi identities express the fact that the boundary of a boundary is always zero. Mathematically this follows by applying Stoke's theorem twice. This is discussed explicitly in the book No-Nonsense Electrodynamics by Schwichtenberg |
- | The motto in this section is: //the higher the level of abstraction, the better//. | + | |
- | </note> | + | |
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+ | <tabbox Abstract> | ||
+ | In general relativity, the Bianchi identity | ||
+ | $$ \nabla R = \nabla \nabla \theta =0 $$ | ||
+ | roughly says "that the sum over a closed two-dimensional surface of rotations induced by Riemannian curvature is equal to zero. [...] Geometrically this means that the density of the moment of rotation induced by Riemannian curvature is equal to zero automatically." ([[https://link.springer.com/article/10.1007%2FBF01882731|Source]]) | ||
<tabbox Why is it interesting?> | <tabbox Why is it interesting?> | ||
<blockquote> | <blockquote> |